[amsat-bb] Re: G-5500 7806 regulator question

Raul Romero CA3SOC ce3soc at gmail.com
Sun Aug 17 10:21:47 PDT 2008


or you insert two diode rectifier in4001 or 1n4007 both ground 7805 and 
ground
one diode rectifier up 0.5 volt for 2 diode 1 volt up

sorry for my bad english

Raul
ce3soc


---------------------------------------------------------------------
"Are you still wasting your time with spam?...
There is a solution!"

Protected by GIANT Company's Spam Inspector
The most powerful anti-spam software available.
http://mail.spaminspector.com


----- Original Message ----- 
From: "i8cvs" <domenico.i8cvs at tin.it>
To: "AMSAT-BB" <amsat-bb at amsat.org>; "Mark L. Hammond" <n8mh at embarqmail.com>
Sent: Saturday, August 16, 2008 9:56 PM
Subject: [amsat-bb] Re: G-5500 7806 regulator question


> ----- Original Message -----
> From: "Mark L. Hammond" <n8mh at embarqmail.com>
> To: <amsat-bb at amsat.org>
> Sent: Sunday, August 17, 2008 1:54 AM
> Subject: [amsat-bb] G-5500 7806 regulator question
>
>> Hello All,
>>
>> It appears that the 7806 voltage regulator in my Yaesu G-5500 control box
> has gone bad; the output is measuring more like 10.8 Volts (!).   This
> explains why both position indicators were off by a factor of 2 (e.g.,
> elevation meter showing 90 deg, array pointing 45; azimuth meter showing 
> 180
> deg, but array pointing 90 deg., and so on).
>>
>> Question---has anybody used a 7805 to replace the 7806 regulator in this
> control box?
>>
>> I don't have a 7806....so this brings the next question--anybody have a
> 7806 (or 2) that they want to sell?)
>>
>> Thanks,
>>
>> Mark L. Hammond  [N8MH]
>>
> Hello, Mark N8MH
>
> Each load across the 7806 regulator is represented by a 500 ohm
> potentiometer with in series a 15 ohm resistor.
>
> The load across the wiper of the 500 ohm potentiometer is 10 K
> and so it is not considered in the following calculation.
>
> If you replace the 7806 with a 7805 regulator the current flowing through 
> a
> resistor R= 15+500 = 515 ohm will be I= 5 / 515 = 0.009708 A and the drop
> of voltage across the 15 ohm resistor will be only
> V= 15 x 0.009708 = 0.145 volt
>
> Since the voltages for the AZ and EL instruments are supplied by the
> operational amplifiers Q3 and Q4 respectively you can adjust VR1 and VR2
> to get again a full scale indication.
>
> The 5 volt voltages for computer control are supplied by the operational
> amplifiers respectively Q3 for the AZ and Q4 for the EL so that when the
> AZ is rotated fully clockwise the potentiometer VR3 must be adjusted to 
> get
> exactly 5 volt DC on pin 6 of the external control 8 pin DIN connector and
> VR4 to get 5 volt DC on pin 1 when the EL is fully rotated by 180 degrees
> (flipping)
>
> Looking the 8 pin DIN connector from the back of control box (external 
> view)
> pin 6 is the first hole clockwise and pin 1 is the second hole clockwise
>
> Conclusion:
>
> It seems that a 7805 will work
>
> 73" de
>
> i8CVS Domenico
>
>
>
>
>
>
>
> _______________________________________________
> Sent via AMSAT-BB at amsat.org. Opinions expressed are those of the author.
> Not an AMSAT-NA member? Join now to support the amateur satellite program!
> Subscription settings: http://amsat.org/mailman/listinfo/amsat-bb 



More information about the AMSAT-BB mailing list